Three Phase Power Calculator

Real, reactive and apparent power from the line current, voltage and power factor

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Supply

V

Line-to-line, 400 V in Australia and New Zealand

Load

A

The current in each line of a balanced load

cos φ

0.8 is a common assumption; 1 for resistive loads

Three-Phase Power

Enter the line current to get the real, reactive and apparent power.

How It's Calculated

For a balanced three-phase load, with the line-to-line voltage, the line current and the angle whose cosine is the power factor:

  • Apparent power: kVA
  • Real power: kW
  • Reactive power: kVAr

Each phase carries a third of each total. In star each phase sees and carries the line current; in delta each phase sees and carries . Either way .

Worked Example

A star-connected load drawing 50 A per line from a 400 V supply at a power factor of 0.85:

  • S = 1.732 × 400 × 50 / 1000 = 34.64 kVA
  • P = 34.64 × 0.85 = 29.44 kW
  • φ = arccos 0.85 = 31.8°, Q = 34.64 × sin 31.8° = 18.25 kVAr
  • Per phase: 9.81 kW, 6.08 kVAr, 11.55 kVA at 230.9 V

Frequently Asked Questions

Three Phase Power Questions Answered

What is the formula for three-phase power?

For a balanced load, P = √3 × VL × IL × cos φ, where VL is the line-to-line voltage, IL the line current and cos φ the power factor. The apparent power is S = √3 × VL × IL and the reactive power Q = √3 × VL × IL × sin φ.

Does it matter whether the load is star or delta?

Not for the total power: the same line voltage and line current give the same kW whichever way the load is connected. What changes is each phase: in star each phase sees VL / √3 (230 V on a 400 V system) and carries the line current; in delta each phase sees the full line voltage and carries IL / √3.

Why not just use 3 × V × I?

That works only with the phase voltage and phase current: P = 3 × Vph × Iph × cos φ. Measured at the switchboard you usually have the line voltage and line current, and substituting Vph = VL / √3 turns the 3 into √3.

How do I work out the power of an unbalanced load?

Calculate each phase on its own, P = Vph × I × cos φ with that phase's current and power factor, and add the three. The √3 formula with an average current is only an approximation when the currents differ.

How much power is 50 A three-phase?

At 400 V, 50 A per line is 34.6 kVA. At a power factor of 0.85 that is about 29.4 kW and 18.2 kVAr; for a resistive load it is the full 34.6 kW.

What is the phase angle?

The angle φ between the voltage and the current, whose cosine is the power factor. A power factor of 0.85 is an angle of about 31.8°; a lagging (inductive) load has the current behind the voltage.

Reviewed by Ahmed Tayeh, electrical engineer at CableHero. The calculator is a design aid: the designer remains responsible for checking the installation against the standards.

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